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JadeNB
on April 8, 2020
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Why is Maxwell's theory so hard to understand? (20...
> How can it be faster considering that they are equivalent?
Computing `ln(e^x)` and `x` are equivalent, but the latter is faster.
Koshkin
on April 8, 2020
[–]
Well, to be fair, these are equal, not just equivalent.
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Computing `ln(e^x)` and `x` are equivalent, but the latter is faster.